contour-integrals
Problem-solving strategies for contour integrals in complex analysis
Packaged view
This page reorganizes the original catalog entry around fit, installability, and workflow context first. The original raw source lives below.
Install command
npx @skill-hub/cli install parcadei-continuous-claude-v3-contour-integrals
Repository
Skill path: .claude/skills/math/complex-analysis/contour-integrals
Problem-solving strategies for contour integrals in complex analysis
Open repositoryBest for
Primary workflow: Ship Full Stack.
Technical facets: Full Stack.
Target audience: everyone.
License: Unknown.
Original source
Catalog source: SkillHub Club.
Repository owner: parcadei.
This is still a mirrored public skill entry. Review the repository before installing into production workflows.
What it helps with
- Install contour-integrals into Claude Code, Codex CLI, Gemini CLI, or OpenCode workflows
- Review https://github.com/parcadei/Continuous-Claude-v3 before adding contour-integrals to shared team environments
- Use contour-integrals for development workflows
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Original source / Raw SKILL.md
---
name: contour-integrals
description: "Problem-solving strategies for contour integrals in complex analysis"
allowed-tools: [Bash, Read]
---
# Contour Integrals
## When to Use
Use this skill when working on contour-integrals problems in complex analysis.
## Decision Tree
1. **Integral Type Selection**
- For integral_{-inf}^{inf} f(x)dx where f decays like 1/x^a, a > 1:
* Use semicircular contour (upper or lower half-plane)
- For integral involving e^{ix} or trigonometric functions:
* Close in upper half-plane for e^{ix} (Jordan's lemma)
* Close in lower half-plane for e^{-ix}
- For integral_0^{2pi} f(cos theta, sin theta)d theta:
* Substitute z = e^{i theta}, use unit circle contour
- For integrand with branch cuts:
* Use keyhole or dogbone contour around cuts
2. **Contour Setup**
- Identify singularities and their locations
- Choose contour that encloses desired singularities
- `sympy_compute.py solve "f(z) = inf"` to find poles
3. **Jordan's Lemma**
- For integral over semicircle of radius R:
- If |f(z)| -> 0 as |z| -> inf, semicircular contribution vanishes
4. **Compute with Residue Theorem**
- oint_C f(z)dz = 2*pi*i * (sum of residues inside C)
- `sympy_compute.py residue "f(z)" --var z --at z0`
## Tool Commands
### Sympy_Residue
```bash
uv run python -m runtime.harness scripts/sympy_compute.py residue "1/(z**2 + 1)" --var z --at I
```
### Sympy_Poles
```bash
uv run python -m runtime.harness scripts/sympy_compute.py solve "z**2 + 1" --var z
```
### Sympy_Integrate
```bash
uv run python -m runtime.harness scripts/sympy_compute.py integrate "1/(x**2 + 1)" --var x --from "-oo" --to "oo"
```
## Key Techniques
*From indexed textbooks:*
- [Complex Analysis (Elias M. Stein, Ram... (Z-Library)] The keyhole contour and one small, connected by a narrow corridor. The interior of Γ, which we denote by Γint, is clearly that region enclosed by the curve, and can be given precise meaning with enough work. We x a point z0 in that If f is holomorphic in a neighborhood of Γ and its interior, interior.
- [Complex Analysis (Elias M. Stein, Ram... (Z-Library)] For the proof, consider a multiple keyhole which has a loop avoiding In each one of the poles. Let the width of the corridors go to zero. Suppose that f is holomorphic in an open set containing a toy contour γ and its interior, except for poles at the points z1, .
- [Complex Analysis (Elias M. Stein, Ram... (Z-Library)] CAUCHY’S THEOREM AND ITS APPLICATIONS The following denition is loosely stated, although its applications will be clear and unambiguous. We call a toy contour any closed curve where the notion of interior is obvious, and a construction similar to that in Theorem 2. Its positive orientation is that for which the interior is to the left as we travel along the toy contour.
- [Complex Analysis (Elias M. Stein, Ram... (Z-Library)] Suppose that f is holomorphic in an open set containing a circle C and its interior, except for poles at the points z1, . The identity γ f (z) dz = 2πi N k=1 reszk f is referred to as the residue formula. Examples The calculus of residues provides a powerful technique to compute a wide range of integrals.
- [Complex analysis an introduction to... (Z-Library)] Hint: Sketch the image of the imaginary axis and apply the argument principle to a large half disk. Evaluation of Definite Integrals. The calculus of residues pro¬ vides a very efficient tool for the evaluation of definite integrals.
## Cognitive Tools Reference
See `.claude/skills/math-mode/SKILL.md` for full tool documentation.